Year 3 answer the following questions in your homework books.
Year 3 – Math Reasoning Questioning
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Year 3 answer the following questions in your homework books.
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259
452
954
951
941
7×7=12
6+6=12
4+8=12
9+3=12
2 I disagree with that you can put all of the counters in the 💯s coulum
7+5=12
8+4=12
9 +3=12
6+6=12
2+10=12
11+1=12
589-70 is not equal to 582
He is wrong because you can have more then 10 counters.
1) sometimes
2) 3 + 9
4 + 8
5 + 7
6 + 6
7 + 5
8 + 4
3) I don’t agree because you can still add the extra ones from the tens and ones colum to the hundreds coloum.
4) 459
395
383
328
250
209
Balraj is incorrect because 589- 70 is 582 no that would be 589 – 7 = 582.
152
228
233
315
454
6+6=12
7+5=12
10+2=12
1+11=12
9+3=12
12+0=12
4+8=12
1+1=2
2+2=4
3+3=6
4+4=8
5+5=10
6+6=12
7+7=14
8+8=16
9+9=18
10+10=20
259
452
954
945
254
245
259
452
549
942
954
459
259
452
954
945
254
245
40+10=50
11+4=15
20+50=70
10+40=50
90+10=100
14+0=0
80+20=100
13+20=23
20+10=30
20+40=60
10+10=20
1+11=12
2+10=12
3+9=12
To make 589
5 hundreds. 8 tens 9 Ones
1+11=12
2+10=12
3+9=12
4+8=12
5+7=12
6+6=12
7+5=12
8+4=12
9+3=12
10+2=12
11+1=12
12+0=12
456
345
123
528
356
109
1+11=12
2+10=12
3+9=12
4+8=12
5+7=12
6+6=12
7+5=12
8+4=12
9+3=12
10+2=12
11+1=12
12+0=12
457
345
123
528
356
109
3+9=12
4+8=12
5+7=12
6+6=12
It is wrong because you took away seven ones then Seven tens.The real answer is 519.Here is the question it is 589-70=519.
Captain Conjecture is not right.
Largest 3 digit number that we can make by changing tens is 891 and not 811.
Possible numbers in increasing order are..
109
152
228
233
315
454
259,295,249,245,294,254
594,542,529,549,524,592
924,954,925,952,945,942
429,425,459,452,492,495
7+5=12
11+1=12
10+2=12
6+6=12
9+3=12
8+4=12
1+11=12
2+10=12
9+3=12 1.
7+5=12
8+4=12
6+6=12
NO because he took away 7 ones from 589.But the answer is…..2.
589-70=519
Ordering numbers:
459
385
373
328
254
109
1. They did not takeaway 70 they said 582 but that was wrong the real answer it is 512
259
452
954
945
254
245
Always because 9+3,8+4 and 6+6 makes 12.
Wrong
589-70=519 is the real one.
No you can make 1000 using ten counters.
2 5 9 4
You can make
249 259 294 295
459 429 492 495
594 592 529 549
945 954 924 925 942 952
1.Because 5+7=12 where 2 is in the ones column. Another example to prove it 15+17=32.
2. 589-70=519 because 0 takeaway 9 is 9 and 7 takeaway 8 is 1 and there is nothing to takeaway from 5.
3.No, because 999 is the largest 3-digit number.
4.456
345
123
128
456
009
5. 249
259
452
442
954
944
7+5=12
9+3=12
8+4=12
6+6=12
5+7=12
3+9=12
4+8=12
589-70=582 is not correct the real answer is 519.
I do agree because they used most dots in the 100s column
459
295
303
228
158
109
954
945
254
245
Balraj is incorrect because 589- 70 is 582 no that would be 589 – 7 = 582. So that’s basically never. He’s incorrect because the largest number that you could make is 1,000 instead of 800. So that’s sometimes.
003,009,028,050,305 and 450
10 more than 2 is 12, 10 less than 2 is -2. 10 more than 5 is 15 10 less is -5. 10 more than 9 is 19 10 less is -9. 10 more than 4 is 14 10 less is -4. That’s basically sometimes
By Marwa
7+5=12
9+3=12
8+4=12
6+6=12
5+7=12
3+9=12
4+8=12
589-70=582 is not correct the real answer is 519.
I do agree because they used most dots in the 100s column
459
295
303
228
158
109
954
945
254
245
I am doing this maths homework in my homework book.
Alwas 7 add 7 = 12 ones colom are to ones.
that makes 14 Leyad R