To crack the code,I got the letters that had the least amount of possibilities.That was A+A=B.Then,I found all the possibilities and tried the other codes with the possibilities.To find the all the possibilities for A+A=B I had to work systematically.

A+A=B 4+4=8

AXA=DF 4X4=16

A+C=DE 4+9=13

C+C=DB 9+9=18

CXC=BD 9X9=81

AXC=EF 4X9=36

A=4

B=8

C=9

D=1

E=3

F=6

G=5

A=4

B=8

C=9

D=1

E=3

F=6

G=5

A+A=B(4+4=8)

AXA=DF(4X4=16)

A+C=DE(4+9=13)

C+C=DB(9+9=18)

CXC=DB(9X9=81)

AXC=EF(4X9=36)

A=4, B=8, C=9, D=1, E=3, F=6 and G=5.

A+A=B AxA=DF A+C=DE

4+4=8 4×4=16 4+9=13

C+C=DB CxC=BD AxC=EF

9+9=18 9×9=81 4×9=36

A is 4,B is 8, C is 9,D is 1,E is 3,F is 6

And G is 5.

1) A+A (4+4=8) A4

2) AxA=DF(4×4=16) B8

3) A+C=DE(4+9=19) C9

4) C+C=DB(9+9=18) D1

5) CxC=BD(9×9=81) E3

6) AxC=EF(4×9=36) F6

G=5.

A=3

B=6

A×A=9

A+c=6

C+c=6

C×C=9

A×C=9

A=3 3+3=6

B=6. 3 x 3=(1 x 9)

D=1. 3+5=(8 x 1)

F=9

C=5.

G=4

E=8

I can’t get it to work for any of the other sums

A is 4, B is 8, C is 9, D is 1, E is 3, F is 6 and

G is 5.

1. A+A=B which is 4+4=8

2. AxA=DF which is 4×4=16

3. A+C=DE which is 4+9=13

4. C+C=DB which is 9+9=18

5. CxC=BD which is 9×9=81

6. AxC=EF which is 4×9=36

I had to do trial and error and try different possibilities to get the answer.

A+A=B (4+4=8) A=4

AxA=DF(4×4=16) B=8

A+C=DE(4+9=13) C=9

C+C=DB(9+9=18) D=1

CxC=BD(9×9=81) E=3

AxC=EF(4×9=36) F=6

G=5

A+A=B (4+4=8)

AxA=DF(4×4=16)

A+C=DE(4+9=13)

C+C=DB(9+9=18)

CxC=BD(9×9=81)

AxC=EF(4×9=36)

A=4

B=8

C=9

D=1

E=3

F=6

G=5

A+A=B (4+4=8)

AxA=DF (4×4=16)

AxC=EF (4×9=36)

C+C=DB (9+9=18)

CxC=BD (9×9=81)

AxC=EF (4×9=36)

To crack the code,I got the letters that had the least amount of possibilities.That was A+A=B.Then,I found all the possibilities and tried the other codes with the possibilities.To find the all the possibilities for A+A=B I had to work systematically.

For this question i will be using a systematic approach to find my answer. This will help me because I can go back and check my answers.

A+A=B (4+4=8)

AxA=DF (4×4=16)

AxC=EF (4×9=36)

C+C=DB (9+9=18)

CxC=BD (9×9=81)

AxC=EF (4×9=36)

A=4 B=8 C=9 D=1 E=3 F=6

Working out is provided in homework book.

There is 7 letters that need numbers so it is going to be trial and error .

a=4

b=8

c=9

d=1

e=3

f=6

g=5

A+A=B [4+4=8]

A*A=DF [4*4=16]

A+C=DE [4+9+13]

C+C=DB [9+9=18]

C*C=BD [9*9=81]

A*C=EF [4*9=36]

I did trial and error on a piece of paper at home an got this answer

1.A+A=B (4+4=8)

2.C+C=DB (9+9=18)

3.A+A=DF (4X4=16)

4.CXC=BD (9X9=81)

5.A+C=DE (4+9=13)

6.AXC=EF (4X9=36) A=4 B=8 C=9 D=1 E=3 F=6

I think I’ve answered all the questions. There are 6 letters, but there are 7 numbers. There’s no G.

1.3+3=6

2.9×9=81

3.9+5=14

4.9+9=18

5.4×4=16

6.9×6=54

A=9

B=8

C=6

D=5

E=4

F=3

G=2