# Year 6 Maths Challenge

Each letter from A to G is a code for one of these digits:

1, 3, 4, 5, 6, 8, 9

Crack the code.

 A + A = B A x A = DF A + C = DE C + C = DB C x C = BD A x C = EF

## 15 thoughts on “Year 6 Maths Challenge”

1. Arif Areeba

A+A=B 4+4=8
AXA=DF 4X4=16
A+C=DE 4+9=13
C+C=DB 9+9=18
CXC=BD 9X9=81
AXC=EF 4X9=36

A=4
B=8
C=9
D=1
E=3
F=6
G=5

2. Hasan Omar

A=4
B=8
C=9
D=1
E=3
F=6
G=5
A+A=B(4+4=8)
AXA=DF(4X4=16)
A+C=DE(4+9=13)
C+C=DB(9+9=18)
CXC=DB(9X9=81)
AXC=EF(4X9=36)

3. Haider Zahra

A=4, B=8, C=9, D=1, E=3, F=6 and G=5.

A+A=B AxA=DF A+C=DE
4+4=8 4×4=16 4+9=13

C+C=DB CxC=BD AxC=EF
9+9=18 9×9=81 4×9=36

4. Tranca Corina

A is 4,B is 8, C is 9,D is 1,E is 3,F is 6
And G is 5.

1) A+A (4+4=8) A4
2) AxA=DF(4×4=16) B8
3) A+C=DE(4+9=19) C9
4) C+C=DB(9+9=18) D1
5) CxC=BD(9×9=81) E3
6) AxC=EF(4×9=36) F6
G=5.

5. Sirapins Arnis

A=3
B=6
A×A=9
A+c=6
C+c=6
C×C=9
A×C=9

6. Hussain Atif

A=3 3+3=6
B=6. 3 x 3=(1 x 9)
D=1. 3+5=(8 x 1)
F=9
C=5.
G=4
E=8
I can’t get it to work for any of the other sums

7. Husna Abdulkayoum

A is 4, B is 8, C is 9, D is 1, E is 3, F is 6 and
G is 5.

1. A+A=B which is 4+4=8

2. AxA=DF which is 4×4=16

3. A+C=DE which is 4+9=13

4. C+C=DB which is 9+9=18

5. CxC=BD which is 9×9=81

6. AxC=EF which is 4×9=36

I had to do trial and error and try different possibilities to get the answer.

8. Finger Hamze

A+A=B (4+4=8) A=4
AxA=DF(4×4=16) B=8
A+C=DE(4+9=13) C=9
C+C=DB(9+9=18) D=1
CxC=BD(9×9=81) E=3
AxC=EF(4×9=36) F=6
G=5

9. Brooks Joshua

A+A=B (4+4=8)
AxA=DF(4×4=16)
A+C=DE(4+9=13)
C+C=DB(9+9=18)
CxC=BD(9×9=81)
AxC=EF(4×9=36)

10. Shah Khushi

A=4
B=8
C=9
D=1
E=3
F=6
G=5
A+A=B (4+4=8)
AxA=DF (4×4=16)
AxC=EF (4×9=36)
C+C=DB (9+9=18)
CxC=BD (9×9=81)
AxC=EF (4×9=36)

To crack the code,I got the letters that had the least amount of possibilities.That was A+A=B.Then,I found all the possibilities and tried the other codes with the possibilities.To find the all the possibilities for A+A=B I had to work systematically.

11. Clare Ciara

For this question i will be using a systematic approach to find my answer. This will help me because I can go back and check my answers.

A+A=B (4+4=8)
AxA=DF (4×4=16)
AxC=EF (4×9=36)
C+C=DB (9+9=18)
CxC=BD (9×9=81)
AxC=EF (4×9=36)
A=4 B=8 C=9 D=1 E=3 F=6

Working out is provided in homework book.

12. Jackson Chanelle

There is 7 letters that need numbers so it is going to be trial and error .

a=4
b=8
c=9
d=1
e=3
f=6
g=5

A+A=B [4+4=8]
A*A=DF [4*4=16]
A+C=DE [4+9+13]
C+C=DB [9+9=18]
C*C=BD [9*9=81]
A*C=EF [4*9=36]

I did trial and error on a piece of paper at home an got this answer

1.A+A=B (4+4=8)
2.C+C=DB (9+9=18)
3.A+A=DF (4X4=16)
4.CXC=BD (9X9=81)
5.A+C=DE (4+9=13)
6.AXC=EF (4X9=36) A=4 B=8 C=9 D=1 E=3 F=6

I think I’ve answered all the questions. There are 6 letters, but there are 7 numbers. There’s no G.

14. Bhattacharjee Priyangshu

1.3+3=6
2.9×9=81
3.9+5=14
4.9+9=18
5.4×4=16
6.9×6=54

• Pharell Richards

A=9
B=8
C=6
D=5
E=4
F=3
G=2